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A Texas mother celebrated Valentine's Day this year by giving birth to two sets of identical twin boys, an event with slimmer odds than winning the national lottery, carrying a one in 70 million chance. The four brothers were delivered at 31 weeks to Tressa Montalvo, 36, via caesarean section at the Woman's Hospital of Texas in Houston, according to a news release from the hospital. Montalvo and her husband, Manuel, were not using fertility drugs and had just hoped for a brother or sister for their two-year-old son, Memphis, according to the release. "We planned the pregnancy � I guess we just succeeded a little too much," Tressa Montalvo said, according to the release. When Montalvo was 10 weeks pregnant, her physician told her she was having twins, and on a subsequent visit, the doctor detected a third heartbeat. The Montalvos were later told they were having four babies � not quadruplets but two sets of twins. The odds of delivering two sets of naturally occurring identical twins is somewhere in the range of one in 70 million, according to the hospital. Two boys shared one placenta and the two other boys shared another placenta. Ace and Blaine were born at 8:51am on 14 February and weighed 3lb 10oz (1.64 kg) and 3lb 15oz (1.79 kg) respectively. Cash and Dylan followed a minute later, weighing 2lb 15oz (1.33 kg), and 3lb 6oz (1.53 kg) respectively. "We tried to stick to the A-B-C-D theme when naming them," Tressa said. "We didn't expect it, we were trying for just one and we were blessed with four." Manuel said in the release that they were not finished yet � he still wants a girl.